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Microsoft 070-461 Deutsch Exam Overview:

Certification Vendor:Microsoft
Exam Name:Querying Microsoft SQL Server 2012/2014
Exam Number:70-461
Related Certifications:MCSE: Data Platform
MCSA: SQL Server 2012/2014
MCSE: Business Intelligence
Available Languages:Japanese, Chinese (Simplified), English, French, German, Portuguese (Brazil)
Passing Score:700 / 1000
Certificate Validity Period:Retired Jan 31, 2021; MCSA credential does not expire
Real Exam Qty:40-60
Exam Duration:120-150
Exam Format:Active screen, Drag and drop, Build list, Multiple select, Multiple choice
Exam Price:$80 USD
Recommended Training:Microsoft Official Course 20461: Querying Microsoft SQL Server 2014
Exam Registration:Microsoft Learn Exam Page
Sample Questions: DOWNLOAD DEMO
Exam Way:Previously delivered via Prometric test centers and online proctoring; no longer available
Pre Condition:Recommended 2+ years of hands-on experience with SQL Server and Transact-SQL; no mandatory prerequisites
Official Syllabus URL:https://learn.microsoft.com/en-us/credentials/certifications/exams/70-461/

Microsoft 070-461 Deutsch Exam Syllabus Topics:

SectionWeightObjectives
Create Database Objects20-25%- Create and alter tables
- Work with data types, collation, and nullability
- Create and modify views, indexed views
- Define constraints (primary key, foreign key, unique, default, check)
- Create and modify stored procedures, triggers, user-defined functions
Troubleshoot and Optimize Queries25-30%- Resolve locking, blocking, and concurrency issues
- Use DMVs and query hints
- Identify performance bottlenecks
- Optimize joins, subqueries, and data access
- Analyze execution plans, statistics, indexes
Work with Data25-30%- Work with grouping, grouping sets, pivot/unpivot
- Write SELECT queries, filter and sort data
- Apply built-in functions, aggregate functions, window functions
- Use subqueries, CTEs, derived tables
- Join multiple tables, apply inner/outer/cross joins
Modify Data20-25%- Merge data from multiple sources
- Modify data via views and stored procedures
- Use output clause, identity columns, sequences
- Manage transactions and error handling
- Insert, update, and delete data

070-461 Deutsch Exam FAQ — Measure Your Ability

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Recommended 2+ years of hands-on experience with SQL Server and Transact-SQL; no mandatory prerequisites Eligibility rules change over time, so verify the current requirements on the official page (official 070-461 Deutsch exam page) before registering.

The Microsoft Querying Microsoft SQL Server 2012/2014 (070-461 Deutsch Version) is Microsoft's certification exam for MCSA: SQL Server 2012/2014, at the Associate level. Employers read it as a measure of individual ability in routine technical work. Related credentials include MCSA: SQL Server 2012/2014, MCSE: Data Platform, MCSE: Business Intelligence.

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The Microsoft Querying Microsoft SQL Server 2012/2014 (070-461 Deutsch Version) blueprint spans 4 domains — including Modify Data (20-25%), Work with Data (25-30%), Troubleshoot and Optimize Queries (25-30%). Our material stays closely linked to these knowledge points; the complete outline above lists every subtopic.

Microsoft Querying Microsoft SQL Server 2012/2014 (070-461 Deutsch Version) Sample Questions:

Sie entwerfen ein Auftragserfassungssystem, das eine SQL Server-Datenbank verwendet. Die Datenbank enthält die folgenden Tabellen:

Sie müssen sicherstellen, dass Bestellungen nur für Kunden mit einem Kontostand von Null zur Tabelle Bestellungen hinzugefügt werden.
Wie müssen Sie die entsprechende Transact-SQL-Anweisung ausfüllen? Wählen Sie zum Beantworten die richtige Transact-SQL-Anweisung aus jeder Liste im Antwortbereich aus.

Reveal Solution  Discussion  0

Correct Answer:


Explanation:
The Transact SQL CREATE TRIGGER command creates a DML, DDL, or logon trigger. A trigger is a special kind of stored procedure that automatically executes when an event occurs in the database server. DML triggers execute when a user tries to modify data through a data manipulation language (DML) event. DML events are INSERT, UPDATE, or DELETE statements on a table or view. These triggers fire when any valid event is fired, regardless of whether or not any table rows are affected.
Partial syntax is:
CREATE TRIGGER [ schema_name . ]trigger_name
ON { table | view }
[ WITH <dml_trigger_option> [ ,...n ] ]
{ FOR | AFTER | INSTEAD OF }
{ [ INSERT ] [ , ] [ UPDATE ] [ , ] [ DELETE ] }
Reference:
https://msdn.microsoft.com/en-us/library/ms189799.aspx

Sie entwickeln eine Microsoft SQL Server 2012-Datenbank.
Sie müssen eine gespeicherte Prozedur erstellen und aufrufen, die die folgenden Anforderungen erfüllt:
* Akzeptiert einen einzelnen Eingabeparameter für CustomerID.
* Gibt eine einzelne Ganzzahl an die aufrufende Anwendung zurück.
Welche Transact-SQL-Anweisung oder -Anweisungen sollten Sie verwenden? (Jede richtige Antwort stellt einen Teil der Lösung dar. Wählen Sie alle zutreffenden Antworten aus.)

  • A. DECLARE @CustomerRatingByCustomer INT
    EXECUTE dbo.GetCustomerRating
    @CustomerID = 1745,
    @CustomerRating = @CustomerRatingByCustomer OUTPUT
  • B. CREATE PROCEDURE dbo.GetCustomerRating
    @CustomerID INT,
    @CustomerRating INT OUTPUT
    WIE
    NOCOUNT EINSTELLEN
    SELECT @CustomerRating = CustomerOrders / CustomerValue
    VON Kunden
    WHERE CustomerID = @CustomerID
    RÜCKKEHR
    GEHEN
  • C. DECLARE @CustomerRatingByCustomer INT
    DECLARE @Result INT
    EXECUTE @Result = dbo.GetCustomerRating
    1745,
    @CustomerRatingByCustomer
  • D. EXECUTE dbo.GetCustomerRating 1745
  • E. CREATE PROCEDURE dbo.GetCustomerRating
    @CustomerID INT
    WIE
    DECLARE @Result INT
    NOCOUNT EINSTELLEN
    SELECT @Result = CustomerOrders / CustomerValue
    VON Kunden
    WHERE CustomerID = @CustomerID
    RETURNS @Result
    GEHEN
  • F. CREATE PROCEDURE dbo.GetCustomerRating
    @CustomerID INT,
    @CustomerRating INT OUTPUT
    WIE
    NOCOUNT EINSTELLEN
    SELECT @Result = CustomerOrders / CustomerValue
    VON Kunden
    WHERE CustomerID = @CustomerID
    RETURN @Result
    GEHEN
Reveal Solution  Discussion  0

Correct Answer: A,B  🗳️

Sie entwickeln eine Microsoft SQL Server 2012-Datenbank.
Sie müssen eine gespeicherte Prozedur erstellen und aufrufen, die die folgenden Anforderungen erfüllt:
* Akzeptiert einen einzelnen Eingabeparameter für CustomerID.
* Gibt eine einzelne Ganzzahl an die aufrufende Anwendung zurück.
Welche Transact-SQL-Anweisung oder -Anweisungen sollten Sie verwenden? (Jede richtige Antwort stellt einen Teil der Lösung dar. Wählen Sie alle zutreffenden Antworten aus.)

  • A. CREATE PROCEDURE dbo.GetCustomerRating
    @CustomerID INT,
    @CustomerRating INT OUTPUT
    WIE
    NOCOUNT EINSETZEN
    SELECT @CustomerRating = CustomerOrders / CustomerValue
    VON Kunden
    WHERE CustomerID = @CustomerID
    RÜCKKEHR
    GEHEN
  • B. DECLARE @CustomerRatingByCustomer INT
    EXECUTE dbo.GetCustomerRating
    @CustomerID = 1745,
    @CustomerRating = @CustomerRatingByCustomer OUTPUT
  • C. DECLARE @CustomerRatingByCustomer INT
    DECLARE @Result INT
    EXECUTE @Result = dbo.GetCustomerRating
    1745,
    @CustomerRatingByCustomer
  • D. VERFAHREN ERSTELLEN dbo.GetCustomerRating
    @CustomerID INT
    WIE
    DECLARE @Result INT
    NOCOUNT EINSETZEN
    SELECT @Result = CustomerOrders / CustomerValue
    VON Kunden
    WHERE CustomerID = @CustomerID
    RETURNS @Result
    GEHEN
  • E. EXECUTE dbo.GetCustomerRating 1745
  • F. CREATE PROCEDURE dbo.GetCustomerRating
    @CustomerID INT,
    @CustomerRating INT OUTPUT
    WIE
    NOCOUNT EINSETZEN
    SELECT @Result = CustomerOrders / CustomerValue
    VON Kunden
    WHERE CustomerID = @CustomerID
    RETURN @Result
    GEHEN
Reveal Solution  Discussion  0

Correct Answer: A,B  🗳️

Sie haben eine Datenbank, die die in der Ausstellung gezeigten Tabellen enthält. (Klicken Sie auf die Schaltfläche Ausstellen).

Sie müssen eine Abfrage für einen Bericht erstellen. Die Abfrage muss die folgenden Anforderungen erfüllen:
* Verwenden Sie KEINE Objekttrennzeichen.
* Geben Sie zuerst die neuesten Bestellungen zurück.
* Verwenden Sie die erste Initiale der Tabelle als Alias.
* Geben Sie für jeden Kunden das letzte Bestelldatum zurück.
* Rufen Sie den Nachnamen der Person ab, die die Bestellung aufgegeben hat.
* Geben Sie das Bestelldatum in einer Spalte mit dem Namen MostRecentOrderDate zurück, die als letzte Spalte im Bericht angezeigt wird.
Die Lösung muss den ANSI SQL-99-Standard unterstützen.
Welches Codesegment sollten Sie verwenden?
Um zu antworten, geben Sie den richtigen Code in den Antwortbereich ein.

  • A. SELECT C.LastName, MAX(O.OrderDate) AS MostRecentOrderDate
    FROM Customers AS C INNER JOIN Orders AS O
    ON C.CustomerID = O.CustomerID
    GROUP BY C.LastName
    ORDER BY MostRecentOrderDate DESC
  • B. SELECT C.LastName, MAX(O.OrderDate) AS MostRecentOrderDate
    FROM Customers AS C INNER JOIN Orders AS O
    ON C.CustomerID
    GROUP BY C.LastName
    ORDER BY MostRecentOrderDate DESC
Reveal Solution  Discussion  0

Correct Answer: A  🗳️

Sie erstellen eine Tabelle mit den Spalten StudentCode, SubjectCode und Marks, um die Halbjahresnoten für die Schüler aufzuzeichnen. Die Tabelle enthält Noten von 50 Schülern für verschiedene Fächer.
Sie müssen sicherstellen, dass die obere Hälfte der Schüler, geordnet nach ihren Durchschnittsnoten, den Rang 1 und die übrigen Schüler den Rang 2 erhalten. Welche Transact-SQL-Abfrage sollten Sie verwenden?

  • A. SELECT StudentCode as Code,
    DENSE_RANK () ÜBER (ORDER BY AVG (Marks) DESC) ALS Wert
    VON StudentMarks
    GROUP BY StudentCode
  • B. SELECT StudentCode AS Code, Markiert AS Value FROM (
    SELECT StudentCode, Marks AS Marks,
    RANK () OVER (PARTITION NACH SubjectCode ORDER NACH Marks DESC) AS Rank
    FROM StudentMarks) tmp
    WO Rang = 1
  • C. SELECT StudentCode as Code,
    RANG () ÜBER (ORDER BY AVG (Marks) DESC) ALS Wert
    VON StudentMarks
    GROUP BY StudentCode
  • D. SELECT StudentCode AS Code, markiert AS Value FROM (
    SELECT StudentCode, Marks AS Marks,
    RANK () OVER (PARTITION BY SubjectCode ORDER BY Markiert ASC) AS Rank
    FROM StudentMarks) tmp
    WO Rang = 1
  • E. SELECT StudentCode AS Code, markiert AS Value FROM (
    SELECT StudentCode, Marks AS Marks,
    RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) ALS Rang
    FROM StudentMarks) tmp
    WO Rang = 1
  • F. SELECT StudentCode as Code,
    NTILE (2) OVER (BESTELLUNG NACH AVG (Marks) DESC) AS-Wert
    VON StudentMarks
    GROUP BY StudentCode
  • G. SELECT StudentCode AS Code, Markiert AS Value FROM (
    SELECT StudentCode, Marks AS Marks,
    RANK () OVER (PARTITION BY StudentCode ORDER BY ASC-Zeichen) AS Rank
    FROM StudentMarks) tmp
    WO Rang = 1
  • H. SELECT ID, Name, Markierungen,
    DENSE_RANK () ÜBER (ORDER BY Markiert DESC) ALS Rang
    VON StudentMarks
Reveal Solution  Discussion  0

Correct Answer: F  🗳️

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