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Microsoft 070-461 Deutsch Exam Overview:
| Certification Vendor: | Microsoft |
|---|---|
| Exam Name: | Querying Microsoft SQL Server 2012/2014 |
| Exam Number: | 70-461 |
| Related Certifications: | MCSE: Data Platform MCSA: SQL Server 2012/2014 MCSE: Business Intelligence |
| Available Languages: | Japanese, Chinese (Simplified), English, French, German, Portuguese (Brazil) |
| Passing Score: | 700 / 1000 |
| Certificate Validity Period: | Retired Jan 31, 2021; MCSA credential does not expire |
| Real Exam Qty: | 40-60 |
| Exam Duration: | 120-150 |
| Exam Format: | Active screen, Drag and drop, Build list, Multiple select, Multiple choice |
| Exam Price: | $80 USD |
| Recommended Training: | Microsoft Official Course 20461: Querying Microsoft SQL Server 2014 |
| Exam Registration: | Microsoft Learn Exam Page |
| Sample Questions: | DOWNLOAD DEMO |
| Exam Way: | Previously delivered via Prometric test centers and online proctoring; no longer available |
| Pre Condition: | Recommended 2+ years of hands-on experience with SQL Server and Transact-SQL; no mandatory prerequisites |
| Official Syllabus URL: | https://learn.microsoft.com/en-us/credentials/certifications/exams/70-461/ |
Microsoft 070-461 Deutsch Exam Syllabus Topics:
| Section | Weight | Objectives |
|---|---|---|
| Create Database Objects | 20-25% | - Create and alter tables - Work with data types, collation, and nullability - Create and modify views, indexed views - Define constraints (primary key, foreign key, unique, default, check) - Create and modify stored procedures, triggers, user-defined functions |
| Troubleshoot and Optimize Queries | 25-30% | - Resolve locking, blocking, and concurrency issues - Use DMVs and query hints - Identify performance bottlenecks - Optimize joins, subqueries, and data access - Analyze execution plans, statistics, indexes |
| Work with Data | 25-30% | - Work with grouping, grouping sets, pivot/unpivot - Write SELECT queries, filter and sort data - Apply built-in functions, aggregate functions, window functions - Use subqueries, CTEs, derived tables - Join multiple tables, apply inner/outer/cross joins |
| Modify Data | 20-25% | - Merge data from multiple sources - Modify data via views and stored procedures - Use output clause, identity columns, sequences - Manage transactions and error handling - Insert, update, and delete data |
070-461 Deutsch Exam FAQ — Measure Your Ability
Upon successful payment, our system emails the Microsoft Querying Microsoft SQL Server 2012/2014 (070-461 Deutsch Version) material automatically within about a minute, with 24/7 help if nothing arrives within 2 hours. If you fail the corresponding 070-461 Deutsch exam within 60 days of purchase, we refund the full amount: send a scanned enrollment slip plus the official Score Report PDF within 2 days of the exam, processed within 7 days. Excluded: exams within 3 days of purchase, candidate names that don't match the payer, and free or expired products. Or exchange for two equal-value products free.
Recommended 2+ years of hands-on experience with SQL Server and Transact-SQL; no mandatory prerequisites Eligibility rules change over time, so verify the current requirements on the official page (official 070-461 Deutsch exam page) before registering.
The Microsoft Querying Microsoft SQL Server 2012/2014 (070-461 Deutsch Version) is Microsoft's certification exam for MCSA: SQL Server 2012/2014, at the Associate level. Employers read it as a measure of individual ability in routine technical work. Related credentials include MCSA: SQL Server 2012/2014, MCSE: Data Platform, MCSE: Business Intelligence.
Yes:
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Yes — we provide the free PDF demo of the Microsoft Querying Microsoft SQL Server 2012/2014 (070-461 Deutsch Version) dumps so you can look at the content and gain a further understanding before paying. Purchases include 365 days of free updates by email; renew afterward at 50% off.
The Microsoft Querying Microsoft SQL Server 2012/2014 (070-461 Deutsch Version) blueprint spans 4 domains — including Modify Data (20-25%), Work with Data (25-30%), Troubleshoot and Optimize Queries (25-30%). Our material stays closely linked to these knowledge points; the complete outline above lists every subtopic.
Microsoft Querying Microsoft SQL Server 2012/2014 (070-461 Deutsch Version) Sample Questions:
Sie entwerfen ein Auftragserfassungssystem, das eine SQL Server-Datenbank verwendet. Die Datenbank enthält die folgenden Tabellen:
Sie müssen sicherstellen, dass Bestellungen nur für Kunden mit einem Kontostand von Null zur Tabelle Bestellungen hinzugefügt werden.
Wie müssen Sie die entsprechende Transact-SQL-Anweisung ausfüllen? Wählen Sie zum Beantworten die richtige Transact-SQL-Anweisung aus jeder Liste im Antwortbereich aus.
Correct Answer:

Explanation:
The Transact SQL CREATE TRIGGER command creates a DML, DDL, or logon trigger. A trigger is a special kind of stored procedure that automatically executes when an event occurs in the database server. DML triggers execute when a user tries to modify data through a data manipulation language (DML) event. DML events are INSERT, UPDATE, or DELETE statements on a table or view. These triggers fire when any valid event is fired, regardless of whether or not any table rows are affected.
Partial syntax is:
CREATE TRIGGER [ schema_name . ]trigger_name
ON { table | view }
[ WITH <dml_trigger_option> [ ,...n ] ]
{ FOR | AFTER | INSTEAD OF }
{ [ INSERT ] [ , ] [ UPDATE ] [ , ] [ DELETE ] }
Reference:
https://msdn.microsoft.com/en-us/library/ms189799.aspx
Sie entwickeln eine Microsoft SQL Server 2012-Datenbank.
Sie müssen eine gespeicherte Prozedur erstellen und aufrufen, die die folgenden Anforderungen erfüllt:
* Akzeptiert einen einzelnen Eingabeparameter für CustomerID.
* Gibt eine einzelne Ganzzahl an die aufrufende Anwendung zurück.
Welche Transact-SQL-Anweisung oder -Anweisungen sollten Sie verwenden? (Jede richtige Antwort stellt einen Teil der Lösung dar. Wählen Sie alle zutreffenden Antworten aus.)
- A. DECLARE @CustomerRatingByCustomer INT
EXECUTE dbo.GetCustomerRating
@CustomerID = 1745,
@CustomerRating = @CustomerRatingByCustomer OUTPUT - B. CREATE PROCEDURE dbo.GetCustomerRating
@CustomerID INT,
@CustomerRating INT OUTPUT
WIE
NOCOUNT EINSTELLEN
SELECT @CustomerRating = CustomerOrders / CustomerValue
VON Kunden
WHERE CustomerID = @CustomerID
RÜCKKEHR
GEHEN - C. DECLARE @CustomerRatingByCustomer INT
DECLARE @Result INT
EXECUTE @Result = dbo.GetCustomerRating
1745,
@CustomerRatingByCustomer - D. EXECUTE dbo.GetCustomerRating 1745
- E. CREATE PROCEDURE dbo.GetCustomerRating
@CustomerID INT
WIE
DECLARE @Result INT
NOCOUNT EINSTELLEN
SELECT @Result = CustomerOrders / CustomerValue
VON Kunden
WHERE CustomerID = @CustomerID
RETURNS @Result
GEHEN - F. CREATE PROCEDURE dbo.GetCustomerRating
@CustomerID INT,
@CustomerRating INT OUTPUT
WIE
NOCOUNT EINSTELLEN
SELECT @Result = CustomerOrders / CustomerValue
VON Kunden
WHERE CustomerID = @CustomerID
RETURN @Result
GEHEN
Correct Answer: A,B 🗳️
Sie entwickeln eine Microsoft SQL Server 2012-Datenbank.
Sie müssen eine gespeicherte Prozedur erstellen und aufrufen, die die folgenden Anforderungen erfüllt:
* Akzeptiert einen einzelnen Eingabeparameter für CustomerID.
* Gibt eine einzelne Ganzzahl an die aufrufende Anwendung zurück.
Welche Transact-SQL-Anweisung oder -Anweisungen sollten Sie verwenden? (Jede richtige Antwort stellt einen Teil der Lösung dar. Wählen Sie alle zutreffenden Antworten aus.)
- A. CREATE PROCEDURE dbo.GetCustomerRating
@CustomerID INT,
@CustomerRating INT OUTPUT
WIE
NOCOUNT EINSETZEN
SELECT @CustomerRating = CustomerOrders / CustomerValue
VON Kunden
WHERE CustomerID = @CustomerID
RÜCKKEHR
GEHEN - B. DECLARE @CustomerRatingByCustomer INT
EXECUTE dbo.GetCustomerRating
@CustomerID = 1745,
@CustomerRating = @CustomerRatingByCustomer OUTPUT - C. DECLARE @CustomerRatingByCustomer INT
DECLARE @Result INT
EXECUTE @Result = dbo.GetCustomerRating
1745,
@CustomerRatingByCustomer - D. VERFAHREN ERSTELLEN dbo.GetCustomerRating
@CustomerID INT
WIE
DECLARE @Result INT
NOCOUNT EINSETZEN
SELECT @Result = CustomerOrders / CustomerValue
VON Kunden
WHERE CustomerID = @CustomerID
RETURNS @Result
GEHEN - E. EXECUTE dbo.GetCustomerRating 1745
- F. CREATE PROCEDURE dbo.GetCustomerRating
@CustomerID INT,
@CustomerRating INT OUTPUT
WIE
NOCOUNT EINSETZEN
SELECT @Result = CustomerOrders / CustomerValue
VON Kunden
WHERE CustomerID = @CustomerID
RETURN @Result
GEHEN
Correct Answer: A,B 🗳️
Sie haben eine Datenbank, die die in der Ausstellung gezeigten Tabellen enthält. (Klicken Sie auf die Schaltfläche Ausstellen).
Sie müssen eine Abfrage für einen Bericht erstellen. Die Abfrage muss die folgenden Anforderungen erfüllen:
* Verwenden Sie KEINE Objekttrennzeichen.
* Geben Sie zuerst die neuesten Bestellungen zurück.
* Verwenden Sie die erste Initiale der Tabelle als Alias.
* Geben Sie für jeden Kunden das letzte Bestelldatum zurück.
* Rufen Sie den Nachnamen der Person ab, die die Bestellung aufgegeben hat.
* Geben Sie das Bestelldatum in einer Spalte mit dem Namen MostRecentOrderDate zurück, die als letzte Spalte im Bericht angezeigt wird.
Die Lösung muss den ANSI SQL-99-Standard unterstützen.
Welches Codesegment sollten Sie verwenden?
Um zu antworten, geben Sie den richtigen Code in den Antwortbereich ein.
- A. SELECT C.LastName, MAX(O.OrderDate) AS MostRecentOrderDate
FROM Customers AS C INNER JOIN Orders AS O
ON C.CustomerID = O.CustomerID
GROUP BY C.LastName
ORDER BY MostRecentOrderDate DESC - B. SELECT C.LastName, MAX(O.OrderDate) AS MostRecentOrderDate
FROM Customers AS C INNER JOIN Orders AS O
ON C.CustomerID
GROUP BY C.LastName
ORDER BY MostRecentOrderDate DESC
Correct Answer: A 🗳️
Sie erstellen eine Tabelle mit den Spalten StudentCode, SubjectCode und Marks, um die Halbjahresnoten für die Schüler aufzuzeichnen. Die Tabelle enthält Noten von 50 Schülern für verschiedene Fächer.
Sie müssen sicherstellen, dass die obere Hälfte der Schüler, geordnet nach ihren Durchschnittsnoten, den Rang 1 und die übrigen Schüler den Rang 2 erhalten. Welche Transact-SQL-Abfrage sollten Sie verwenden?
- A. SELECT StudentCode as Code,
DENSE_RANK () ÜBER (ORDER BY AVG (Marks) DESC) ALS Wert
VON StudentMarks
GROUP BY StudentCode - B. SELECT StudentCode AS Code, Markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION NACH SubjectCode ORDER NACH Marks DESC) AS Rank
FROM StudentMarks) tmp
WO Rang = 1 - C. SELECT StudentCode as Code,
RANG () ÜBER (ORDER BY AVG (Marks) DESC) ALS Wert
VON StudentMarks
GROUP BY StudentCode - D. SELECT StudentCode AS Code, markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Markiert ASC) AS Rank
FROM StudentMarks) tmp
WO Rang = 1 - E. SELECT StudentCode AS Code, markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) ALS Rang
FROM StudentMarks) tmp
WO Rang = 1 - F. SELECT StudentCode as Code,
NTILE (2) OVER (BESTELLUNG NACH AVG (Marks) DESC) AS-Wert
VON StudentMarks
GROUP BY StudentCode - G. SELECT StudentCode AS Code, Markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY ASC-Zeichen) AS Rank
FROM StudentMarks) tmp
WO Rang = 1 - H. SELECT ID, Name, Markierungen,
DENSE_RANK () ÜBER (ORDER BY Markiert DESC) ALS Rang
VON StudentMarks
Correct Answer: F 🗳️
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