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H3CSE-RS-RT Sample Questions:

1. 如图所示,路由器接口配置 IPv6 链路本地地址 FE80::2009:1 ,并在链路上通告前缀 2009:10:121::/64 ,那么该链路上的节点所获得的网关地址是。

A) fe80::1
B) fe80::2009:1
C) 2009:10:121::2009:1
D) 2009:10:121::/64

2. 组网如图所示, RTA 、 RTB 位于 AS 1001 , RTC 、 RTD 、 RTE 位于 AS 1002 , AS 1001 向 AS 1002 发布 BGP 路由 11.11.11.0/24 , RTC 、 RTD 的 BGP 主要配置如下,如果 RTE 、 RTC 的互联链路中断, RTE 访问 11.11.11.0/24 网段,优先经过哪条广域链路 ?
[RTC]
Bgp 1002
Preference 20 170 200
PeerRTA as-number 1001
PeerRTD as-number 1002
PeerRTA route-policsetmed import
Route-policsetmed permit node 10
Applcost 100
[RTD]
Bgp 1002
Preference 20 170 200
PeerRTB as-number 1001
PeerRTC as-number 1002
PeerRTA route-policsetmed import
Route-policsetmed permit node 10
Applcost 200

A) 优先经过广域链路一,因为 RTC 的 MED 100<RTD 的 MED200
B) 优先经过广域链路二,因为 RTD 上 eBGP 路由优先。
C) 优先经过广域链路一,因为 RTC 上 eBGP 路由优先。
D) 优先经过广域链路二,因为 RTD 的 MED 200>[RTC 的 MED 100 。

3. B. GP 路由表中有两条明细路由 10.10.1.0/24 、 10.10.2.0/24 ,用户要求对外发布 10.10.1.0/24 和汇聚路由 10.10.0.0/16 ,不对外发布 10.10.2.0/24 ,请问应该如何实现 ?

A) acl number 2000 Rule permit source 10.10.2.0 0.0.0.255 Bgp 100 Aggregate 10.10.0.0 255.255.0.0 suppress-polictest Route-polictest permit node 10 If-match acl 2000
B) acl number 2000 Rule permit source 10.10.2.0 0.0.0.255 Bgp 100 Aggregate 10.10.0.0 255.255.0.0 origin-polictest Route-polictest permit node 10 If-match acl 2000
C) acl number 2000 Rule permit source 10.10.2.0 0.0.0.255 Bgp 100 Aggregate 10.10.0.0 255.255.0.0 suppress-polictest Route-polictest dennode 10 If-match acl 2000 Route-polictest permit node 20
D) acl number 2000 Rule permit source 10.10.2.0 0.0.0.255 Bgp 100 Aggregate 10.10.0.0 255.255.0.0 origin-polictest Route-polictest dennode 10 If-match acl 2000 Route-polictest permit node 20

4. 在 MSR 路由器 RTA 上执行 displaospf routing 命令后,路由器输出如下 :
OSPF Process 1 with Router ID 1.1.1.1
Routing Tables
Routing for Network
Destination Cost Tpe NextHop AdvRouter Area
192.168.1.0/24 1 Transit 192.168.1.1 2.2.2.2 0.0.0.0
192.168.2.0/24 2 Inter 192.168.1.2 2.2.2.2 0.0.0.0
Routing for ASEs
Destination Cost Tpe Tag NextHop AdvRouter
192.168.100.1/32 1 Tpe1 1 192.168.1.2 3.3.3.3
192.168.101.1/32 1 Tpe1 1 192.168.1.2 3.3.3.3
192.168.102.1/32 1 Tpe2 1 192.168.1.2 3.3.3.3
192.168.103.1/32 1 Tpe2 1 192.168.1.2 3.3.3.3
Total Nets: 6
Intra Area: 1 Inter Area: 1 ASE: 4 NSSA: 0
从以上输出可以判断。

A) 192.168.102.1 是接受到的 Tpe2 LSA
B) 192.168.2.0 这个网段不在 Area0 内
C) 总共有 6 条 OSPF 路由,其中 1 条区域内路由, 1 条区域间路由, 4 条外部路由
D) 192.168.100.1 是接受到的 Tpe1 LSA

5. 路由表中有 4 条路由 10.0.0.0/24 、 10.0.1.0/24 、 10.0.2.0/24 、 10.0.3.0/24 。
如要进行路由聚合,则正确的聚合后路由是。

A) 10.0.0.0/23
B) 10.0.0.0/24
C) 10.0.0.0/25
D) 10.0.0.0/22

Solutions: